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Question

CH3COOH(l) + C2H5OH(l) CH3COOC2H5(l) + H2O(l);Kc=4

In the above reaction, one mole of each of acetic acid and alcohol are heated in the presence of little conc. H2SO4. On equilibrium being attained


A

1 mole of ethyl acetate is formed

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B

2 mole of ethyl acetate are formed

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C

1/2 moles of ethyl acetate is formed

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D

2/3 moles of ethyl acetate is formed

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Solution

The correct option is D i.e 2/3 moles of ethyl acetate is formed.
CH3COOH(l)+C2H5OH(l)CH3COOC2H5(l)+H2O(l)
1 1 0 0
1-x 1-x x x
Kc=[CH3COOC2H5][H2O][CH3COOH][C2H5OH]
4=x2[1x]2
2=x1x
x = 2-2x
x = 23

On equilibrium being attained 2/3 moles of ethyl acetate is formed


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