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Question

Charge Q is given a displacement r=a^i+b^j in an electric field E=E1^i+E2^j. The work done is :

A
Q(E1a+E2b)
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B
Q(E1a)2+(E2b)2
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C
Q(E1+E2)a2+b2
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D
Q(E21+E22)2a2+b2
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Solution

The correct option is A Q(E1a+E2b)
Work done in the presence of electric field E is W=F.r=qE.r
W=Q[(E1^i+E2^j).(a^i+b^j)]
W=Q(E1a+E2b)

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