CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Check continuity f(x)=|x|+1,x<00,x=0|x|+1,x>0

Open in App
Solution

at x=0
R.H.L limx0+hf(x)
=limh0|h|+1
=limh0h+1
=1
L.H.L limx0hf(x)
=limh0|h|+1
=limh0h+1
=1
and f(0)=0
Since R.H.L = L.H.L
so, limit exist at x=0
since R.H.l = L.H.L f(0)
Therefore f(x) is not continuous at x=0

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Continuity of a Function
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon