Question

Check whether $6^n$ can end with the digit $0$ for any natural number $n$.

Answer 1

If any digit has the last digit $10$ that means it divisible by $10.$

The factor of $10=2\times 5,$

So value of $6^n$ should be divisible by $2$ and $5.$

Both $6^n$ is divisible by $2$ but not divisible by $5.$

So, it can not end with $0.$