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Question

Check whether $$6^n$$ can end with the digit $$0$$ for any natural number $$n$$.


Solution

If any digit has the last digit $$10$$ that means it divisible by $$10.$$

The factor of $$10 = 2 \times 5,$$ 

So value of $$6^n$$ should be divisible by $$2$$ and $$5.$$

Both $$6^n$$ is divisible by $$2$$ but not divisible by $$5.$$

So, it can not end with $$0.$$

Mathematics
RS Agarwal
Standard X

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