Check whether the first polynomial is a factor of the second polynomial by dividing the second polynomial by the first polynomial: (i) t2−3,2t4+3t3−2t2−9t−12 (ii) x2+3x+1,3x4+5x3−7x2+2x+2 (iii) x3−3x+1,x5−4x3+x2+3x+1
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Solution
(i) Given polynomials t2−3,2t4+3t3−2t2−9t−12 Division of 2t4+3t3−2t2−9t−12 by t2−3
Remainder is 0, hence t2−3 is a factor of 2t4+3t3−2t2−9t−12
(ii) Given x2+3x+1,3x4+5x3−7x2+2x+2 Division of 3x4+5x3−7x2+2x+2 by x2+3x+1 is
Remainder is 0, hence x2+3x+1 is a factor of 3x4+5x3−7x2+2x+2
(iii) x3−3x+1,x5−4x3+x2+3x+1 Division of x5−4x3+x2+3x+1 by x3−3x+1 is
Remainder is 2, hence x3−3x+1 is not a factor of x5−4x3+x2+3x+1