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Question

Chlorine exists in two isotopic forms, Cl37 and Cl35 but its atomic mass is 35.5. This indicates the ratio of Cl37 and Cl35 is approximately:

A
1:2
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B
1:1
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C
1:3
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D
3:1
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Solution

The correct option is C 1:3
Let relative abundance of Cl-37 be A1% with mass M1=37 amu

The relative abundance of Cl-35 = A2% with mass, M2=35 amu

where A1+A2=100

Thus A2%=(100A1)%

Using average atomic mass, Mavg=M1A1+M2A2A1+A2

Mavg=37×A1+35×(100A1)A1+(100A1)=2A1+3500100

Given that: Mavg=35.5

2A1+3500100=35.5

2A1=35.5×1003500=50

A1=502=25 and A2=100A1=10025 =75

Thus the ratio of isotope abundance of Cl37toCl35 is A1:A2=25:75=1:3

So, the correct option is C

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