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Question

Choose the correct answer from the alternatives given :
When the polynomial $$(6x^4 \, + \, 8x^3 \, + \, 17x^2 \, + \, 21x \, + \, 7)$$ is divided by $$(3x^2 \, + \, 4x \, + \, 1)$$ , the remainder is (ax + b). Therefore,


A
a = 1, b = 2
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B
a = 1, b = 2
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C
a = 2, b = 1
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D
a = 1, b = 2
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Solution

The correct option is A a = $$1$$, b = $$2$$

According to the question,
+ 2 = ax + b
a = 1 & b = +2

Mathematics

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