Question

# Choose the correct answer from the alternatives given :When the polynomial $$(6x^4 \, + \, 8x^3 \, + \, 17x^2 \, + \, 21x \, + \, 7)$$ is divided by $$(3x^2 \, + \, 4x \, + \, 1)$$ , the remainder is (ax + b). Therefore,

A
a = 1, b = 2
B
a = 1, b = 2
C
a = 2, b = 1
D
a = 1, b = 2

Solution

## The correct option is A a = $$1$$, b = $$2$$According to the question,x + 2 = ax + ba = 1 & b = +2Mathematics

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