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Question

Choose the correct answer.

If f(a+bx)=f(x), then bax f(x) dx is equal to(a)a+b2baf(bx)dx(b)a+b2baf(b+x)dx(c)ba2baf(x) dx(d)a+b2baf(x) dx

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Solution

Let bax f(x)dx ........(i)

Then, by a property of definite integrals

I=ba(a+bx)f(a+bx)dx=ba(a+bx)f(x) dx ...(ii) ( Given f(a+bx)=f(x))

On adding Eqs. (i) and (ii), we get

2I=ba(a+b)f(x) dx I=a+b2baf(x) dx

Hence, the option (d) is correct.


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