Choose the correct answer The value of -k-k-k- isa Zerob -1c 1d

We have î.(ĵ×k̂) + ĵ. (k̂×î) + k̂(î×î) = î . î +ĵ.ĵ+k̂.k̂ [∵ĵ×k̂ = î, k̂×î = ĵ, î×ĵ=k̂] =1+1+1=3 [∵î.î=ĵ.ĵ=k̂.k̂=1] ...

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Choose the correct answer
The value of $^i . (^j \times^k) +^j . (^k \times^i) +^k (^i \times^j)$ is
a) Zero
b) - 1
c) 1
d) 3

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^i \cdot (^j \times^k) +^j \cdot (^k \times^i) +^k \cdot (^j \times^i)

(^i \times^j) \cdot^k +^i \cdot^j .

^i,^j,^k

^i \cdot (^j \times^k) +^j \cdot (^i \times^k) +^k \cdot (^i \times^j)

μ,

μ^i +^j +^k,^i + μ^j +^k,^i +^j + μ^k

L_{1} : \to r = (\begin{matrix} ^i +^j +^k \end{matrix}) + λ (\begin{matrix} - 2^i +^j -^k \end{matrix}) a n d L_{2} : \to r =^j + μ (\begin{matrix} ^i -^j \end{matrix})

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