Choose the correct option.
(Given that all the adjacent points are equidistant from each other)

AB > BD > BG > AC

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AC > CD > DG > BG

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AD > BE > FE > GE

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AE > AD > BD > BC

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Solution

The correct option is D AE > AD > BD > BC
Suppose the length of each segment is x.
AB = BC = CD = DE = EF = FG = x
AE= AB + BC + CD + DE = 4x
AD = AB + BC + CD = 3x
BD = BC + CD = 2x .
BC = x
Since 4x > 3x > 2x > x
We have, AE > AD > BD >BC

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Similar questions

Diagonal AC and BD of quadrilateral ABCD intersects each other at point O.

Prove that AB + BC + CD + AD < 2 (AC + BD).

In the above triangle ABC, AB = BC. BD is perpendicular to AC and EC bisects the angle $∠ A C B$ . Which of the following is correct?

A B = A C, ∠ A = 48^{\circ}

∠ A C D = 18^{\circ}

A D ⊥ B C

C D > B D

A C > A B

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