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Question

Choose the correct statement for Ca(OH)2 when the pH of a 5×102 M solution of Ca(NO3)2​ is adjusted to 10.
[Given that: Ksp(Ca(OH)2)=5×106M3]

A
Ca(OH)2 precipitation will take place.
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B
Ca(OH)2 precipitation will not take place.
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C
For Ca(OH)2, Qsp=Ksp
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D
Can not predicted.
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Solution

The correct option is B Ca(OH)2 precipitation will not take place.
At 25oC, pH=10 is given ,
So , [H+]=1010 M[OH]=104 M
Ca(NO3)2 is a strong electrolyte. The dissociation of Ca(NO3)2 is given below :
Ca(NO3)2(s)Ca2+(aq)+2NO3(aq)[Ca2+]=5×102 M

Qsp=[Ca2+][OH]2Qsp=(5×102)(104)2Qsp=5×1010
Given ,Ksp(Ca(OH)2=5×106M3
Qsp<Ksp
So , precipitation will not take place.

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