Question

# Choose the incorrect statement among the following regarding the given reactions:

A
MgSO4 can be stored in Cu vessel
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B
Cu displaces Mg from MgSO4
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C
Cu2+ has higher oxidising power than Mg2+
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D
Mg will reduce CuSO4
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Solution

## The correct option is B Cu displaces Mg from MgSO4Standard reduction potentials (SRP) of the half cell electrodes are calculated and arranged in a series of increasing order which is known as electrochemical series. The standard electrode potential of H+/H2 couple is zero. Here, a negative E0 signifies that it has high tendency to get oxidised and the redox couple is a stronger reducing agent than the H+/H2 couple. A positive E0 signifies that it has high tendency to get reduced and the redox couple is a stronger oxidising agent than the H+/H2 couple. Mg2+/Mg couple has less E0 value than Cu2+/Cu. So, Cu2+ gets reduced and has higher oxidising power than Mg2+ For Mg(s) to reduce CuSO4(aq), the following reaction's E0cell must be positive. Mg(s)+Cu2+(aq)→Cu(s)+Mg2+(aq) E0cell=SRP cathode- SRP anode E0cell=E0Cu2+/Cu−E0Mg2+/MgE0cell=(0.34−(−2.36)) VE0cell=+2.7 V Thus option (d) is correct. E0cell value for the reverse reaction is negative : Cu(s)+Mg2+(aq)→Mg(s)+Cu2+(aq) So, MgSO4 can be stored in Cu vessel Thus, statement (b) is incorrect.

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