CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

Circles are described on the sides of a triangle as diameters. Prove that the circles on any two sides intersect each other on the third side (or third side produced).


Solution

Given: In ΔABC, circles are drawn with sides AB and AC as diameter.

To prove: Circles drawn on AB and AC intersect at D which lies on BC, the third side.

Construction: Draw AD BC.

Proof : ADBC

ADB=ADC=90o

So, the circles drawn on sides AB and AC as diameter will pass through D.

Hence, circles drawn on two sides of a triangle pass through D, which lies on the third side.

flag
 Suggest corrections
thumbs-up
 
1 Upvotes


Similar questions
QuestionImage
QuestionImage
View More...


Same exercise questions
QuestionImage
QuestionImage
View More...


People also searched for
QuestionImage
QuestionImage
View More...



footer-image