Question

Column-I contains four statements following reason and Column-II consists of four options (P,Q,R,S)
$P\to$- If both statement and reason are true and reason is correct explanation of statement.
$Q\to$-If both statement and reason are true and reason is not correct explanation of statement.
$R\to$- If statement is correct and reason is incorrect.
$S\to$- If both statement and reason are incorrect.

Answer 1

$A=S\left(4\right)$ $\Rightarrow Pb{I}_4$ is unstable. On ionization $Pb{I}_4$ gives $P{b}^{4+}$ and $I^{-}$ ions and reduces to $P{b}^{4+}$ to $P{b}^{2+}$ and oxidizes to $I_2$. Simple halides form in the oxidation states $+7$ and $+3$. Iodide stabilizes the lower oxidation states $+3to+1$ and fluorides the higher oxidation states $+7to+4$

$B=R\left(3\right)$$\Rightarrow$ White phosphorus is more reactive than red phosphorus. White phosphorus has a tetrahedral basic unit where four phosphorus atoms arranged at the four corners of a tetrahedron are joined together by a total of six single bonds. This creates a very highly strained system which is unstable and very reactive. Red phosphorus is a polymer of $P_4$ tetrahedra, which has much less angular strain.

$C=Q\left(2\right)\Rightarrow$ Peroxysulfuric acid $\left(H_{2}S{O}_5\right)$ known as Caro's acid. Sulphur atom is in $s{p}^3$ hybridized state as the structure of acid is $HO-\stackrel{\stackrel{O}{||}}{\underset{\underset{O}{||}}{S}}-O-OH$ and Caro's acid contains one peroxy $O_2^{-2}$ linkage.

$D=R\left(3\right)\Rightarrow$ Both $S{O}_2$ and chlorine are bleaching agents. Bleaching action of chlorine is permanent while that of $S{O}_2$ is temporary.When $Cl$ reacts with water, it produces nascent oxygen. The bleaching action of $Cl$ is based on oxidation while that of $S{O}_2$ is based on reuction. $S{O}_2$ removes oxygen from the dye.