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Question

Column-I: Subshell Column-II: Number of spherical nodes Column-III: Radial plot

The only correct combination for the last electron of Cl− is:


A

(IV) (i) (R)

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B

(IV) (iv) (P)

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C

(III) (iii) (Q)

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D

(II) (ii) (P)

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Solution

The correct option is A

(IV) (i) (R)


Cl:1s2 2s2 2p6 3s2 3p6

For last electron, subshell is 3p.

Number of spherical nodes =nl1

= 3 - 1 - 1 = 1


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