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Byju's Answer
Standard XII
Chemistry
Chemical Properties of Boron Family
Common alum i...
Question
Common alum is:
A
K
2
S
O
4
⋅
A
l
2
(
S
O
4
)
3
⋅
24
H
2
O
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B
(
N
H
4
)
2
S
O
4
⋅
F
e
S
O
4
⋅
6
H
2
O
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C
K
2
S
O
4
⋅
C
r
2
(
S
O
4
)
3
⋅
24
H
2
O
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D
K
2
S
O
4
⋅
F
e
2
(
S
O
4
)
3
⋅
24
H
2
O
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Solution
The correct option is
D
K
2
S
O
4
⋅
A
l
2
(
S
O
4
)
3
⋅
24
H
2
O
Potassium alum is the common alum of commerce whose chemical formula is
K
2
S
O
4
.
A
l
2
(
S
O
4
)
3
.24
H
2
O
Ammonium alum is
(
N
H
4
)
S
O
4
.
A
l
2
(
S
O
4
)
3
.24
H
2
O
.
Chrome alum is
K
2
S
O
4
.
C
r
2
(
S
O
4
)
3
.24
H
2
O
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0
Similar questions
Q.
K
2
C
r
2
O
7
–
––––––––
–
+
7
H
2
S
O
4
+
6
F
e
S
O
4
⟶
K
2
S
O
4
+
C
r
2
(
S
O
4
)
3
+
3
F
e
2
(
S
O
4
)
3
+
7
H
2
O
The equivalent weight of the underlined species (by taking its molecular weight as
M
) is
:
Q.
Is
(
K
2
S
O
4
⋅
C
r
2
(
S
O
)
4
)
3
⋅
24
H
2
O
correct formula of chrome alum ?
If yes enter 1, else enter 0.
Q.
In the chemical reaction,
K
2
C
r
2
O
7
+
x
H
2
S
O
4
+
y
S
O
2
⟶
K
2
S
O
4
+
C
r
2
(
S
O
4
)
3
+
z
H
2
O
x
,
y
and
z
are, respectively
:
Q.
How many gram ions of
S
O
−
2
4
are present in
1.25
mole of
K
2
S
O
4
⋅
A
l
2
(
S
O
4
)
3
⋅
24
H
2
O
.
Q.
After balancing the equation,
K
2
C
r
2
O
7
+
X
H
2
S
O
4
+
Y
S
O
2
→
K
2
S
O
4
+
C
r
2
(
S
O
4
)
3
+
Z
H
2
O
The values of X, Y and Z obtained will be respectively.
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