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Question

Compare the speed of the three particles A,B and C as per the distance-time graph shown below.

A
vA>vB>vC
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B
vA>vC>vB
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C
vB>vA>vC
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D
vC>vA>vB
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Solution

The correct option is A vA>vB>vC
Given distance-time graph as

As we know that speed of the particle is the slope of the distance-time curve
So, speed of particle A is given by
vA=25020=12.5 m/s
similarly, speed of particle B is given by
vB=250604 m/s
Also, speed of particle C is given by
vC=100701.4 m/s
So, we can conclude here that vA>vB>vC

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