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Question

Complete solution set of x25x+7+x25x14=21 is -

A
[2,7]
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B
(,2][7,)
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C
[7,)
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D
(,2]
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Solution

The correct option is A [2,7]
|a|+|b|=|ab|
After squaring on both sides we get,
|a||b|=ab
ab0

(x25x+7)(x25x14)0
Here, x25x+7>0 xR
x25x140
(x7)(x+2)0
x [2,7]

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