Question

Complete the given balanced equation and find out the missing term.
${}_6^{14}C{\to }_4^{10}Be+?$

• A. ${}_{-1}^0\beta$
• B. ${}_1^0\beta$
• C. ${}_2^{4}He$
• D. ${}_0^0\gamma$
• E. ${}_0^{1}n$

Answer 1

Answer: (C)

${}_2^{4}He$

The balanced equation is
${}_6^{14}C{\to }_4^{10}Be{+}_2^{4}He$
The missing term is ${}_2^{4}He$.
The atomic number of the missing term is observed by subtracting the atomic number of $Be$ from the atomic number of $C$.
The mass number of the missing term is observed by subtracting the mass number of $Be$ from the atomic number of $C$.
It is an alpha particle.