    Question

# Complete the last column of the table. S. No. Equation Value Say, whether the equation is satisfied. (Yes/No) (i) x + 3 = 0 x = 3 - (ii) x + 3 = 0 x = 0 - (iii) x + 3 = 0 x = − 3 - (iv) x − 7 = 1 x = 7 - (v) x − 7 = 1 x = 8 - (vi) 5x = 25 x = 0 - (vii) 5x = 25 x = 5 - (viii) 5x = 25 x = − 5 - (ix) m = − 6 - (x) m = 0 - (xi) m = 6 -

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Solution

## (i) x + 3 = 0 L.H.S. = x + 3 By putting x = 3, L.H.S. = 3 + 3 = 6 ≠ R.H.S. ∴ No, the equation is not satisfied. (ii) x + 3 = 0 L.H.S. = x + 3 By putting x = 0, L.H.S. = 0 + 3 = 3 ≠ R.H.S. ∴ No, the equation is not satisfied. (iii) x + 3 = 0 L.H.S. = x + 3 By putting x = −3, L.H.S. = − 3 + 3 = 0 = R.H.S. ∴ Yes, the equation is satisfied. (iv) x − 7 = 1 L.H.S. = x − 7 By putting x = 7, L.H.S. = 7 − 7 = 0 ≠ R.H.S. ∴ No, the equation is not satisfied. (v) x − 7 = 1 L.H.S. = x − 7 By putting x = 8, L.H.S. = 8 − 7 = 1 = R.H.S. ∴ Yes, the equation is satisfied. (vi) 5x = 25 L.H.S. = 5x By putting x = 0, L.H.S. = 5 × 0 = 0 ≠ R.H.S. ∴ No, the equation is not satisfied. (vii) 5x = 25 L.H.S. = 5x By putting x = 5, L.H.S. = 5 × 5 = 25 = R.H.S. ∴ Yes, the equation is satisfied. (viii) 5x = 25 L.H.S. = 5x By putting x = −5, L.H.S. = 5 × (−5) = −25 ≠ R.H.S. ∴ No, the equation is not satisfied. (ix) = 2 L.H.S. = By putting m = −6, L. H. S. = ≠ R.H.S. ∴No, the equation is not satisfied. (x) = 2 L.H.S. = By putting m = 0, L.H.S. = ≠ R.H.S. ∴No, the equation is not satisfied. (xi) = 2 L.H.S. = By putting m = 6, L.H.S. = = R.H.S. ∴ Yes, the equation is satisfied.  Suggest Corrections  0      Related Videos   Solving an Equation with the Variable on Both Sides
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