Question

Compound (A) is:

• A. ${CH}_3-\stackrel{\stackrel{{OCH}_3}{|}}{\underset{\underset{{CH}_3}{|}}{C}}-{CH}_2{CH}_{2}Br$
• B. ${CH}_3-\underset{\underset{{CH}_3}{|}}{CH}-\underset{\underset{{OCH}_3}{|}}{CH}-{CH}_{2}Br$
• C. ${CH}_3-\underset{\underset{{CH}_3}{|}}{CH}-{CH}_2-\underset{\underset{{OCH}_3}{|}}{CH}-Br$
• D. ${CH}_3-\stackrel{\stackrel{{OCH}_3}{|}}{\underset{\underset{{CH}_3}{|}}{C}}-\underset{\underset{Br}{|}}{CH}-{CH}_3$

Answer 1

The correct option is A ${CH}_3-\stackrel{\stackrel{{OCH}_3}{|}}{\underset{\underset{{CH}_3}{|}}{C}}-{CH}_2{CH}_{2}Br$

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i. 2-Methoxy-2-methyl propane is obtained by the oxidation of (D) followed by decarboxylation, and thus (D) is

$C{H}_3-\underset{C{H}_3}{\underset{|}{\stackrel{OC{H}_3}{\stackrel{|}{C}}}}-C{H}_{2}C{H}_{2}OH$

ii. (D) is formed by the action of $HN{O}_2$ on (B), thus (B) is

$C{H}_3-\underset{C{H}_3}{\underset{|}{\stackrel{OC{H}_3}{\stackrel{|}{C}}}}-C{H}_{2}C{H}_{2}N{H}_2$

iii. (B) is formed by the action of $N{H}_3$ over (A), a bromoderivative.

$\left(A\right)\Rightarrow C{H}_3-\underset{C{H}_3}{\underset{|}{\stackrel{OC{H}_3}{\stackrel{|}{C}}}}-C{H}_{2}C{H}_{2}Br$

Reactions :

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Option A is correct.