Compound (A) reacts with $[C u (N H_{3})_{2}]^{+}$ and Tollens reagent, but after reaction with alc. KOH it does not give the above test. Compound (A) is:

M e - \equiv - M e

No worries! We‘ve got your back. Try BYJU‘S free classes today!

M e - \equiv - H

No worries! We‘ve got your back. Try BYJU‘S free classes today!

M e - C \equiv C H

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

P h - \equiv - H

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $M e - C \equiv C H$
Terminal alkyne containing four or more C atoms on reaction with alk. KOH isomerises to internal alkynes, which do not gives all the test mentioned. Although (b) and (d) are also terminal aklynes, they do not have sufficient C atoms to be converted to internal alkynes. So the answer is (c)

Suggest Corrections

Similar questions

M e - C | C l H - M e a l c . K O H - ---- \to C H_{3} - C H = C H_{2}

C H_{3} - C H_{2} - C H_{2} - C l a l c . K O H - ---- \to C H_{3} - C H = C H_{2}

M e - C l + N H_{3}

⟶

P h - M e ∣ C ∣ H - O H S O C l_{2} ⟶ C_{5} H_{5} N m e d i u m

R

R - C H = C H_{2}

R

I . M e -

I I . E t -

I I I . {M e}_{2} C H -

I V . {M e}_{3} C -

(i) M e M g B r

(i i) E t M g B r

(i i i) {M e}_{2} C H - M g B r

(i v) {M e}_{3} C - M g B r