Compound 'A' ...

Question

Compound 'A' reacts with $P C l_{5}$ to give 'B' which on treatment with KCN followed by hydrolysis gave propanoic acid as the product. What is 'A'?

Ethane

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Propane

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Ethyl chloride

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Ethyl alcohol

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Solution

The correct option is D Ethyl alcohol
$C_{2} H_{5} O H A + P C l_{5} K C N - -- \to C_{2} H_{5} C N B H C l / H_{2} O - ----- \to C_{2} H_{5} C O O H Propanoic acid$
Option D is correct.

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