CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Comprehension # 2
Following passage explains the effect of temperature on the vapour pressure of the liquid.

Effect of temperature on vapour pressure
The quantity of heat required to evaporate a given liquid at constant temperature is defined as the heat of vaporisation. Variation of vapour pressure with temperature is given by,

Clausius-Clapeyron equation.

logeP=ΔHvapRT+logeA

A liquid is said to be at its boiling temperature if its vapour pressure is equal to external pressure. Therefore, the boiling point of water in particular and of liquids in general decreases as an altitude of a place increases where the external pressure is less than 1atmosphere (normal b.p. of water is 373.15K at 1atmosphere)

On top of mount everest, for example, where the atmospheric pressure is only about 260mmHg, water boils at approximately 71C. Conversely, if the external pressure on a liquid is greater than 1atm, the vapour pressure necessary for boiling than normal boiling is reached later, and the liquid boils at a temperature greater than the normal boiling point.

Clausius-Clapeyron equation can be written in the following form:

A
P=AeΔHvap/RT
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
dlog10PdT=ΔHvap2.303RT2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
dlogePdT=ΔHvapRT2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
P=AeΔHvap/RT
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct options are
A P=AeΔHvap/RT
B dlog10PdT=ΔHvap2.303RT2
2011346_261809_ans_018f9544f2f6466498ee394b3749f340.jpg

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Pascal's Law
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon