Compute the work which must be performed (in $K g f - m$ ) to slowly pump water out of a hemispherical reservoir of radius $R = 0.6 m$

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Solution

Since the center of mass of hemisphere from the top is $h = \frac{3 R}{8}$
Mass of water $m = \frac{2 π R^{3} ρ}{3}$
So work done by pump $W = m g h = \frac{2 g π R^{3} ρ \times 3 R}{3 \times 8} = \frac{g π R^{4} \times 1000}{4} = 102 N$

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Compute the work which must be performed (in Kgf−m) to slowly pump water out of a hemispherical reservoir of radius R=0.6m

Since the center of mass of hemisphere from the top is h=3R8 Mass of water m=2πR3ρ3So work done by pump W=mgh=2gπR3ρ×3R3×8=gπR4×10004=102 N

Compute the work which must be performed (in $K g f - m$ ) to slowly pump water out of a hemispherical reservoir of radius $R = 0.6 m$

Since the center of mass of hemisphere from the top is $h = \frac{3 R}{8}$
Mass of water $m = \frac{2 π R^{3} ρ}{3}$
So work done by pump $W = m g h = \frac{2 g π R^{3} ρ \times 3 R}{3 \times 8} = \frac{g π R^{4} \times 1000}{4} = 102 N$