Conjugate base of $N H_{3}$ is:

N H_{4}^{+}

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N H_{2}^{+}

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N H_{2}^{-}

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N_{2}

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Solution

The correct option is C $N H_{2}^{-}$
Conjugate base :
Species formed by the loss of a proton from an acid is called the conjugate base of that acid.
[Conjugate base has one proton less than the acid]

When $H^{+}$ is removed from $N H_{3}$ we get $N H_{2}^{-}$ .
$N H_{3} - H^{+} ⟶ N H_{2}^{-}$
So, $N H_{2}^{-}$ is the conjugate base of $N H_{3}$ acid.

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N H_{3} + H_{2} O \to N H_{4}^{+} + O H^{-}

Write the conjugate acids for the following Brönsted bases: NH₂^–, NH₃ and HCOO^–.

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