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Question

Consider A = (x+y+z3012) = (azx+zy). The value of a is ___

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Solution

A = (x+y+z3012) = (azx+zy).

Comparing the two matrices, we get

y = -12 ………………….. (1)

x + y + z = -a ……………………. (2)

x + z = 0 ………………….. (3)

From (2) and (3)

a = -y

= -(-12)

= 12


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Algebraic Operations
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