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Question

Consider A = (x+y+z3012) = (azx+zy). The value of a is _________________

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Solution

A = (x+y+z3012) = (azx+zy).

Comparing the two matrices, we get

y = -12 ………………….. (1)

z = 3 ……………………. (2)

x + z = 0

x = -3 ………………….. (3)

-a = x + y + z = -3 -12 +3 = -12

a = 12


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