Question

# Consider a strong base, AOH solution having a pH=11 mixed in an equal volume with another solution of strong base, BOH to give a resultant solution of pH=12. Find the pH of solution containing strong base BOH.

A
13.9
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B
12.8
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C
12.3
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D
13.3
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Solution

## The correct option is C 12.3Solution 1 having strong base AOH: pH=11pOH=14−pHpOH=14−11=3pOH=3−log[OH−]=3[OH−]=10−3C1=10−3 M Solution 2 containing strong base BOH: Let concentration be C2=[OH−] Final solution obtained after mixing: pH=12pOH=14−pHpOH=14−12=2pOH=2−log[OH−]=2[OH−]=10−2 M Concentration (Cf)=10−2 M The volume of two solutions are equal. So, V1=V2=VVf=V1+V2=2VCfVf=C1V1+C2V210−2×2V=(10−3×V)+(C2×V)C2=(2×10−2)−(10−3)C2=[OH−]=0.019 MpOH=−log[OH−]pOH=−log(0.019)pOH≈−log(0.02)pOH=2−log2=(2−0.3)=1.7pH=14−pOH=14−1.7=12.3pH=12.3

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