Consider a two particle system with particles having masses $m_{1}$ and $m_{2}$ . If the first particle is pushed towards the centre of mass through a distance $d$ , by what distance should the second particle be moved, so as to keep the centre of mass at the same position?

d

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\frac{m_{2}}{m_{1}} d

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\frac{m_{1}}{m_{1} + m_{2}} d

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\frac{m_{1}}{m_{2}} d

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Solution

The correct option is D $\frac{m_{1}}{m_{2}} d$
$C O M s h o u l d b e a t t h e s a m e p o s i t i o n m_{1} d + m_{2} x = 0 \Rightarrow x = - \frac{m_{1} d}{m_{2}}$

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