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Question

Consider a young's doluble slit experiment as shown in figure. What should be the slit seperation d in term of wavelength $$\lambda$$ such that the first minima occurs directly in front of the slit $$(S_1)$$ ? 
1332680_f29b00c86ef44685a7b26805536a1eb8.PNG


A
λ2(52)
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B
λ(52)
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C
λ(52)
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D
λ2(52)
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Solution

The correct option is A $$\dfrac{\lambda}{2(\sqrt{5} - 2)}$$
$$x_1 = 2d$$
$$x_2 = \sqrt{5} d$$
$$\Delta x = x_2 - x_1$$
$$\sqrt{5}d - 2d  = \dfrac{ \lambda} {2}$$
$$d = \dfrac{\lambda}{2(\sqrt{5} - 2)}$$

Physics

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