Question

Consider a young's doluble slit experiment as shown in figure. What should be the slit seperation d in term of wavelength $$\lambda$$ such that the first minima occurs directly in front of the slit $$(S_1)$$ ?

A
λ2(52)
B
λ(52)
C
λ(52)
D
λ2(52)

Solution

The correct option is A $$\dfrac{\lambda}{2(\sqrt{5} - 2)}$$$$x_1 = 2d$$$$x_2 = \sqrt{5} d$$$$\Delta x = x_2 - x_1$$$$\sqrt{5}d - 2d = \dfrac{ \lambda} {2}$$$$d = \dfrac{\lambda}{2(\sqrt{5} - 2)}$$Physics

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