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Question

Consider an A.P. a1, a2, a3, such that a3+a5+a8=11 and a4+a2=2, then the value of a1+a6+a7 is

A
8
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B
5
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C
7
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D
9
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Solution

The correct option is C 7
Given that,

a3+a5+a8=11

a+2d+a+4d+a+7d=11

3a+13d=11 (1)

Given,

a4+a2=2

a+3d+a+d=2

a=12d (2)

Putting value of a from (2) in (1), we get

3(12d)+13d=11

7d=14

d=2 and a=5

a1+a6+a7=7

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