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Question

Consider earth satellites in circular orbits. A geostationary satellite must be at a height of about 36000 km from the earth's surface. Will any satellite moving at this height be a geostationary satellite? Will any satellite moving at this height have a time period of 24 hours?

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Solution


T=(gR2T24π2)13-RT=4π2(h+R)3gR2=4×3.142×(36000+6400)3×1099.8×(6400×103)2=24.097 HrWhich implies that it is a geostationary sattelite with time period=24 Hrs.

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