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Question

# Consider following complexes :I: [Fe(H2O)6]2+II :[Fe(CN)6]4âˆ’III :[Ni(CO)4]IV :[Ni(H2O)4]2+V :[Ni(CN)4]2âˆ’Out of this, select the complex with equal magnetic moment :

A
[Fe(CN)6]4 and [Ni(CN)4]2
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B
[Ni(CO)4] and [Fe(CN)6]4
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C
[Ni(H2O)4]2+ and [Ni(CO)4]
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D
None of these
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Solution

## The correct option is D None of these[Fe(H2O)6]2+Fe is in +2 state in above compound as H2O don't have any charge on it.Fe2+−[Ar]3d6There are four unpaired electrons in 3d orbital as H2O is a weak ligand.Magnetic Moment- √n(n+2)- √24 BM [Fe(CN)6]4−x−6=−4 x=+2Fe is in +2 state in above compound.Fe2+−[Ar]3d6There is no unpaired electron because CN− is a strong field ligand and paired the electrons due to high energy difference between t2g level and eg level.Magnetic Moment = 0[Ni(H2O)4]2+Ni is in +2 state in above compound as H2O is neutral.Ni2+−[Ar]3d8There are two unpaired electron in eg level. Magnetic Moment- √n(n+2)- √8 BM [Ni(CN)4]2−x−4=−2 x=+2Ni is in +2 state in above compound.Ni2+−[Ar]3d8There are two unpaired electron in eg level.Magnetic Moment- √n(n+2)- √8 BM Therefore, option D is correct.

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