CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Consider following complexes :

I: [Fe(H2O)6]2+

II :[Fe(CN)6]4−

III :[Ni(CO)4]

IV :[Ni(H2O)4]2+

V :[Ni(CN)4]2−

Out of this, select the complex with maximum number of unpaired electrons.

A
[Fe(CN)6]4
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
[Fe(H2O)6]2+
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
[Ni(CO)4]
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
[Ni(H2O)4]2+
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B [Fe(H2O)6]2+
[Fe(H2O)6]2+
Fe is in +2 state in above compound as H2O don't have any charge on it.
Fe2+[Ar]3d6
There are four unpaired electrons in 3d orbital as H2O is a weak ligand.
[Fe(CN)6]4
x6=4
x=+2
Fe is in +2 state in above compound.
Fe2+[Ar]3d6
There is no unpaired electron because CN is a strong field ligand and paired the electrons due to high energy difference between t2g level and eg level
[Ni(CO)4]
Ni is in 0 state in above compound as CO is neutral.
Ni[Ar]4s23d8
There is no unpaired electron because CO is a strong field ligand and it pushes the two electrons from 4s orbital to 3d orbital to pair the unpaired electron. [Ni(H2O)4]2+
Ni is in +2 state in above compound as H2O is neutral.
Ni2+[Ar]3d8
There are two unpaired electron in eg level.
[Ni(CN)4]2
x4=2
x=+2
Ni is in +2 state in above compound
Ni2+[Ar]3d8
There are two unpaired electron in eg level.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Oxidation States
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon