Question

Consider the addition of HBr to 3,3-dimethyl-1-butene, what is the mechanistic explanation for the formation of observed product?

• A. Protonation of the alkene followed by trapping of carbocation with $B{r}^{-}$
• B. Protonation of the alkene followed by hydride shift and addition of $B{r}^{-}$ to carbocation.
• C. Double bond shift in the alkene followed by the protonation and addition of $B{r}^{-}$ to carbocation.
• D. Protonation of alkene followed by methyl shift and addition of $B{r}^{-}$ to the carbocation.

Answer 1

The correct option is D Protonation of alkene followed by methyl shift and addition of $B{r}^{-}$ to the carbocation.

$\begin{array}{c}\text{The Answer is protonation of alkene followed by methyl}\text{shift and addition of Br to the Carbocation.}\end{array}$