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Question

Consider the circuit shown in the figure. The current i3 is equal to

 
  1. 5 amp
  2. 3 amp
  3. – 3 amp
  4. 56 amp


Solution

The correct option is D 56 amp
Suppose current through different paths of the circuit is as follows.
After applying KVL for loop (1) and loop (2)

We get 28i1=68i1=12A
and 54i2=612i2=13A
Hence i3=i1+i2=56A

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