Question

Consider the equation $-3x^2+c=0$, where $c>0.$ Then the roots of the equation are

• A. Real and equal in magnitude
• B. Real and equal
• C. Non real
• D. None of these

Answer 1

The correct option is A Real and equal in magnitude

$-3x^2+c=0$
$\Rightarrow 3x^2=c$
$\Rightarrow x=\pm \sqrt{\frac{c}{3}},(c>0)$

So, the roots of the equation are equal in magnitude but opposite in sign.