Consider the equation az2+z+1=0 having purely imaginary root where a=cosθ+isinθ,i=√−1 and function f(x)=x3−3x2+3(1+cosθ)x+5, then answer the following questions
ii) Which of the following is true ?
A
f(x)=0 has three but not distinct roots
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B
f(x)=0 has one positive real root
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C
f(x)=0 has one negative real root
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D
f(x)=0 has three real distinct roots
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Solution
The correct option is Cf(x)=0 has one negative real root f(x)=x3−3x2+3(1+cosθ)x+5 (Given) f(x) is increasing ∀x∈R
(From the previous result) f(0)=(0)3−3(0)2+3(0)+5=5
Since, f(x) is increasing function and f(0)=5,
There will always be a point on negative x−axis where f(x) will be 0.
Hence, f(x)=0 has one negative real root.