Question

Consider the following AP sequence: 134, 104, 74,… The $6^{th}$term is

• A. the first negative term
• B. the second negative term
• C. the last positive term
• D. zero

Answer 1

The correct option is A

the first negative term

In the given AP; $a_1=134;d=-30$

$a_n$ = $a_1$ + (n-1)d $\Rightarrow$ $a_6$ = 134 + (6-1)(-30) = -16 and this term is negative.

$a_5$ = $134$ + (5-1)(-30) = 14

Till the fifth term, the terms are all positive. So the sixth term, which is -16 is the first negative term.