Question

Consider the following carbocations.
(i) $C{l}_3{C}^{+}$

(ii) $C{l}_{2}C{H}^{+}$

(iii) $ClC{H}_2^{+}$

(iv) $C{H}_3^{+}$

Order of stability sequence is:

• A. $\left(iv\right)<\left(i\right)<\left(ii\right)<\left(iii\right)$
• B. $\left(i\right)<\left(ii\right)<\left(iii\right)<\left(iv\right)$
• C. $\left(iv\right)<\left(i\right)<\left(iii\right)<\left(ii\right)$
• D. $\left(iv\right)<\left(ii\right)<\left(i\right)<\left(iii\right)$

Answer 1

Answer: (B)

$\left(i\right)<\left(ii\right)<\left(iii\right)<\left(iv\right)$

Because of greater electron-negativity of chlorine atom, the stability of carbocation decreases.