The correct option is C OH− is reducing as well as oxidising agent
In H−C||O−C||O−H, in the presence of OH−. One CHO is oxidised to COO− and other CHO is reduced to CH2OH. Thus, it is not a disproportionation reaction as reduction and oxidation happens within a molecule and therefore it is intramolecular redox reaction. Also, intramolecular redox reaction occurs when we have the oxidizing and reducing agents within one molecule. Thus,H−C||O−C||O−H is reducing as well as oxidising agent.