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Question

Consider the following reaction:
xMnO4+yC2O24+zH+xMn2++2yCO2+z2H2O
The values of x, y and z in the reaction are, respectively: 
  1. 5,2 and 16
  2. 2, 5 and 16
  3. 2, 5 and 8
  4. 5, 2 and 8


Solution

The correct option is B 2, 5 and 16
change in O.N for Mn is -5, change in O.N. for C is +2 for oxalation ion.
Balanced reaction is a simple cross multiplication.
The protons balance out the charges.
2MnO4+5C2O24+16H+2Mn2++10CO2+8H2O

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