Question

Consider the ground state of $$Cr$$ atom ($$Z=24$$). The numbers of electrons with azimuthal quantum numbers, $$\ell=1$$ and $$2$$, are respectively:

A
12 and 4
B
12 and 5
C
16 and 4
D
16 and 5

Solution

The correct option is B $$12$$ and $$5$$Electronic configuration of $$Cr$$($$Z=24$$) $$n$$                      $$l$$$$1{ s }^{ 2 }$$$$1$$$$0$$$$2{ s }^{ 2 }$$$$2$$$$0$$$$2{ p }^{ 6 }$$$$2$$$$1$$$$3{ s }^{ 2 }$$$$3$$$$0$$$$3{ p }^{ 6 }$$$$3$$$$1$$$$3{ d }^{ 5 }$$$$3$$$$2$$$$4{ s }^{ 1 }$$$$4$$$$0$$Thus, the number of electrons with $$l=1$$ are $$12$$ and $$l=2$$ are $$5$$.Chemistry

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