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Question

Consider the ground state of $$Cr$$ atom ($$Z=24$$). The numbers of electrons with azimuthal quantum numbers, $$\ell=1$$ and $$2$$, are respectively:


A
12 and 4
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B
12 and 5
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C
16 and 4
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D
16 and 5
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Solution

The correct option is B $$12$$ and $$5$$

Electronic configuration of $$Cr$$
($$Z=24$$)
 $$n$$                      $$l$$
$$1{ s }^{ 2 }$$$$1$$$$0$$
$$2{ s }^{ 2 }$$$$2$$$$0$$
$$2{ p }^{ 6 }$$$$2$$$$1$$
$$3{ s }^{ 2 }$$$$3$$$$0$$
$$3{ p }^{ 6 }$$$$3$$$$1$$
$$3{ d }^{ 5 }$$$$3$$$$2$$
$$4{ s }^{ 1 }$$$$4$$$$0$$
Thus, the number of electrons with $$l=1$$ are $$12$$ and $$l=2$$ are $$5$$.

Chemistry

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