Question

Consider the ground state of Cr atom (z=24). The numbers of electrons with the azimuthal quantum numbers, l=1 and 2 are respectively

• A. 12 and 4
• B. 12 and 5
• C. 16 and 4
• D. 16 and 5

Answer 1

The correct option is B 12 and 5

The ground state electronic configuration of Cr is $1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}3d^{5}4s^1$
No. of electrons with l=1( p orbital)=6 in 2p6 + 6 in $3p^6=12$
No. of electrons with l=2 d orbital =5 in $3d^5$