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Question

Consider the reaction : Cr2O27+14H++6e2Cr3++7H2O


What is the quantity of electricity in coulombs needed to reduced 1 mol of Cr2O27?

A
6×106C
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B
5.79×105C
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C
5.25×105C
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D
None of these
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Solution

The correct option is C 5.79×105C
Cr2O27+14H++6e2Cr3++7H2O

The valency factor for Chromium is 6.

Applying faraday's first law-
QF=mole×V.f.

Q=mole×V.f.×F

Q=1×6×96500

Q=5.79×105 C

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