Question

# Consider the word ′RAMAYANA′, then the total number of possible wordsWhen all A′s are together is 120When no two A′s are together is 120When it starts with A and ends with A is 360When it starts with any consonant is 210

Solution

## The correct options are A When all A′s are together is 120 B When no two A′s are together is 120 C When it starts with A and ends with A is 360′RAMAYANA′ It has ′R,M,Y,N and 4A′s When all A′s are together, total words will be 5!4!×4!=120 Total words when no two A′s are together Arrange the letters ′R,M,Y,N in alternate manner, such that there will be 5 spaces left, so that can be filled by 5 ways So the total number of words =5×4!=120 When the word starts with A and ends with A Total ways 6!2!=360 When word starts with any consonant is, i.e. by ′R,M,Y,N =4×7!4!=840

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