CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Consider two parallel, conducting frictionless tracks are kept in gravity free space as shown in the figure. A movable conductor PQ, initially kept at OA, given a velocity 10 ms1 towards right. If space contains a magnetic field upon the distance moved by conductor PQ from OA line and given by B=cx(^k)[c=constant=1 S.I. unit]. The mass of conductor PQ is 1 kg and length of PQ is 1 m. Answer the following questions based on above passage.


A
The distance travelled by conductor when its speed is 5 ms1 is(152)13m
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
The heat loss during the time interval t=0 to time t sec, when the speed of conductor is 5 ms1 is 10 J
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
The distance travelled by conductor when its speed is 5 ms1 is (102)13m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
The heat loss during the time interval t=0 to time t sec, when the speed of conductor is 5 ms1 is 50 J
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A The distance travelled by conductor when its speed is 5 ms1 is(152)13m
emf=dϕdt=ddtx0BdA+AdBdte=ddtx0lxdx+lxdxdte=xvl+xvl=2xvl
Current through resistance is
I=2xvlR
Magnetic force is F=IBl=2x2vl2R
Now F=ma

a=vdvdx=2x2vl2mR

Applying limits
510dv=x02x2l2mRdx
+5=2l2mRx33
x=(152)13(a)
Heat produced in R= loss of kinetic energy of rod
H=12×1×(10)2- 12×1×(5)2
H=12[10025]=752 J
Ans : (1)

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Magnetic Field Due to a Current Carrying Wire
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon