Question

Construct a cyclic quadrilateral $ABCD$ where $AB=7$ cm, $\angle A={80}^o$, $AD=4.5$ cm and $BC=5$ cm.

Answer 1

Construction :
1. Draw a rough diagram.
2. Draw a line segment $AB=7$ cm.
3. Through $A$ draw $AX$ such that $\angle XAB={80}^o$.
4. Mark a point $D$ on $AX$ such that $AD=4.5$ cm.
5. Complete the $△ABD$.
6. Draw the $\perp$r of $AB$ and $BD$, they meet at $O$.
7. Draw a circle $O$ and radius as $OA$.
8. Mark a point $C$ on the circle such that $BC=5$ cm.
9. $ABCD$ is the required cyclic quadrilateral.