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Question

Construct a ΔABC in which AB = 6 cm, A=30 and B=60. Construct another ΔABC similar to ΔABC with base AB' = 8 cm.

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Solution

Scale factor fraction numerator AB apostrophe over denominator AB end fraction space equals space 8 over 6 space equals space 4 over 3
The required triangle can be drawn using the following steps:

1. Draw a ΔABC with side AB = 6 cm, ∠A = 30o and ∠B = 60o.

2. Draw a ray AZ making an acute angle with AB on the opposite side of vertex C.

3. Locate 4 points ( as 4 is greater in 4 and 3) A1, A2, A3, and A4 on AZ.

4. Join A3B. Draw a line through A4 parallel to A3B intersecting extended AB at B'.

5. Through B', drawn a line parallel to BC intersecting ray AX at C'.

Hence, ΔAB'C' is the required triangle.



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